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5x^2-5=30x-30
We move all terms to the left:
5x^2-5-(30x-30)=0
We get rid of parentheses
5x^2-30x+30-5=0
We add all the numbers together, and all the variables
5x^2-30x+25=0
a = 5; b = -30; c = +25;
Δ = b2-4ac
Δ = -302-4·5·25
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-20}{2*5}=\frac{10}{10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+20}{2*5}=\frac{50}{10} =5 $
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